Rake-face friction and normal forces are $F=F_c\sin\alpha+F_t\cos\alpha$ and $N=F_c\cos\alpha-F_t\sin\alpha$. Substituting gives F ≈ 427.10 N and N ≈ 838.57 N. Thus $\mu=F/N\approx0.5093$, rounding to **0.51**.
More Machining questions
GATE 2024 PI Q55– Turn a 160 mm diameter,190 mm long workpiece at cutting speed 80π m/min and feed 0.2…
GATE 2024 PI Q58– Orthogonal turning uses cutting speed 2 m/s, feed 0.2 mm/rev and depth 2 mm. Specific…
GATE 2023 PI Q16– An alumina grinding wheel has ANSI designation 51 A 36 K 5 V 23. What does K indicate?
GATE 2023 PI Q17– The directrix and generatrix of a machining operation are shown. Which surface is…
GATE 2023 PI Q56– In orthogonal cutting with rake angle 0°, cutting force is twice thrust force. Find…
GATE 2023 PI Q58– Straight turning uses feed rate 100 mm/min, spindle speed 1600 rpm and ASA tool signature…