Manufacturing Processes II · Machining · 2 marks · Numerical answer
Turn a 160 mm diameter,190 mm long workpiece at cutting speed 80π m/min and feed 0.2 mm/rev. Approach and overrun are 5 mm each. Find machining time (integer minutes).
Spindle speed is $N=V/(\pi D)=80\pi/(\pi\cdot0.160)=500$ rpm. Feed speed is 500(0.2) = 100 mm/min. Total travel is 190+5+5 = 200 mm, so **time = 2 minutes**.
More Machining questions
GATE 2024 PI Q58– Orthogonal turning uses cutting speed 2 m/s, feed 0.2 mm/rev and depth 2 mm. Specific…
GATE 2023 PI Q16– An alumina grinding wheel has ANSI designation 51 A 36 K 5 V 23. What does K indicate?
GATE 2023 PI Q17– The directrix and generatrix of a machining operation are shown. Which surface is…
GATE 2023 PI Q56– In orthogonal cutting with rake angle 0°, cutting force is twice thrust force. Find…
GATE 2023 PI Q58– Straight turning uses feed rate 100 mm/min, spindle speed 1600 rpm and ASA tool signature…
GATE 2022 PI Q29– Orthogonal machining uses a zero-rake single-point tool. Chip-compression ratio is 1.25.…