Manufacturing Processes II · Machining · 2 marks · Numerical answer
Orthogonal turning uses cutting speed 2 m/s, feed 0.2 mm/rev and depth 2 mm. Specific cutting energy is 2 J/mm³. Ignore feed-force power. Find main cutting force (integer N).
Uncut chip area is 0.2(2) = 0.4 mm². Material removal rate at 2000 mm/s is 800 mm³/s, requiring 2(800) = 1600 W. Main force is power/speed = 1600/2 = **800 N**.
More Machining questions
GATE 2023 PI Q16– An alumina grinding wheel has ANSI designation 51 A 36 K 5 V 23. What does K indicate?
GATE 2023 PI Q17– The directrix and generatrix of a machining operation are shown. Which surface is…
GATE 2023 PI Q56– In orthogonal cutting with rake angle 0°, cutting force is twice thrust force. Find…
GATE 2023 PI Q58– Straight turning uses feed rate 100 mm/min, spindle speed 1600 rpm and ASA tool signature…
GATE 2022 PI Q29– Orthogonal machining uses a zero-rake single-point tool. Chip-compression ratio is 1.25.…
GATE 2022 PI Q52– Turning a 20 mm steel bar with an HSS tool gives life 10 min at 400 rpm and 40 min at 200…