In the dimensioned part, the distance from the left outer face to the right edge of slot A is100±0.5 mm. The left end width is40±0.1 mm; the right end width is40±0.2 mm. Find the permissible ± tolerance of slot A in mm (one decimal).
Slot width is the100 mm dimension minus the40 mm left end width, so nominal A=60 mm. In worst-case stacking, half-tolerances add:0.5+0.1=0.6 mm. Thus A=60±0.6 mm. The right end’s40±0.2 dimension lies outside this slot dimension chain and does not enter the calculation.
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