All sizes are mm. Hole limits are $22^{+0.018}_{+0.010}$ and shaft limits are $22^{+0.075}_{+0.004}$. Find clearance magnitude when shaft is at minimum material condition and hole is at maximum material condition (three decimals).
A shaft has minimum material at its smallest diameter: 22.004 mm. A hole has maximum material at its smallest diameter: 22.010 mm. Clearance is 22.010 − 22.004 = **0.006 mm**. The two conditions both select lower dimensional limits because material lies inside the shaft but outside the hole.
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