Euler roots are 1,2, so y=ax+bx². First boundary gives (a+b)−(a+2b)=−b=1, hence b=−1. Second becomes (2−k)a+(4−4k)b=4. For a arbitrary, require k=2; then the b term is (−4)(−1)=4, so the condition holds for every a. **2.00**.
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