The first equation gives u proportional to $e^{-x^2/2}$. Substitute $\phi=e^{-x^2/2}\beta$ into the second equation; the β′ terms cancel and it reduces to β″ + β = 0. The initial conditions give β(0) = 1 and β′(0) = 0, hence β = cos x. Thus φ = cos x times $e^{-x^2/2}$, B.
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