For λ = 1 an eigenvector is (1,1)ᵀ; for λ = −1 it is (2,1)ᵀ. Thus y = a(1,1)ᵀeˣ+b(2,1)ᵀe⁻ˣ. Initial values give a+2b = 1 and a+b = 2, so b = −1,a = 3. **D**.
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