GATE 2022 MA – Question 33
If x²φ″+xφ′+x²φ=0,x>0 has a Frobenius solution $\phi=x^r\sum_{n\ge0}a_nx^n$ with a₀≠0, find r²+1.
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Correct answer: 1 to 1
Explanation
The lowest power xʳ has coefficient [r(r−1)+r]a₀=r²a₀; the x²φ term starts two orders later. Therefore r²=0, and **r²+1=1**.