Use J_(1/2)(x)=√(2/(πx))sin x and J_(−1/2)(x)=√(2/(πx))cos x. At α=1/2, J_(3/2)=J_(1/2)/x−J_(−1/2). At x=π this is √2/π because sinπ=0,cosπ=−1. Thus the square is **2**.
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