Complete the square: f=(x₂+x₁²/2)²+(7/4)x₁⁴≥0, with equality only at the origin. Thus it is a strict global and local minimum. Stationarity also gives x₂=−x₁²/2 and 7x₁³=0, so there is just one stationary point. **D**.
More Multivariable Calculus questions
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