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GATE 2024 AG – Question 35

Agricultural Process Engineering · Evaporation and Drying · 1 mark · Numerical answer

A single-effect evaporator concentrates9090 kg/hour herbal extract from 12% to 20% solids. Feed enters at 300 K and product loss with vapor is negligible. Find product flow, in integer kg/hour.

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Correct answer: 5452 to 5456

Explanation

Nonvolatile solids are conserved. Feed solids rate is $9090(.12)=1090.8$ kg/hour. If product flow is P,$.20P=1090.8$,so **P=5454 kg/hour**. The remainder3636 kg/hour is evaporated water; inlet temperature is unnecessary for this mass balance.

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