An open V-belt joins effective pulley diameters .25 m and .65 m at 1 m centre distance. Find the smaller pulley wrap angle in degrees, to two decimals. Use π=3.14.
For an open belt, $\sin\alpha=(D-d)/(2C)=.40/2=.20$. The small-pulley contact angle is $180^\circ-2\alpha$. Converting arcsin(.2) with 180/3.14 gives **156.91°**. The larger pulley instead has 180°+2α.
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