Let outlet concentration be $.1C_0$. A CSTR requires $V_C=Q(C_0-C)/(kC^2)=90Q/(kC_0)$. A PFR requires $V_P=(Q/k)(1/C-1/C_0)=9Q/(kC_0)$. Their ratio is 90/9=**10,A**. Lower concentration throughout the mixed reactor reduces its second-order reaction rate.
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