At the usual25°C water-ion product, [OH⁻]=10⁻⁸ M. Thus $Q=[Zn^{2+}][OH^-]^2=10^{-3}(10^{-8})^2=10^{-19}$. Ratio=$10^{-19}/(8\times10^{-18})=.0125$, giving **.01** to two decimals. It is below one, indicating undersaturation.
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