Hosts X,Y have a direct 10⁶ bit/s link, distance 10000 km, propagation speed 2×10⁸ m/s. X sends a 50000-byte file as one continuous message. Find transmission delay p and propagation delay q in ms.
Transmission delay is 50000×8/10⁶=0.4 s=400 ms. Distance is 10⁷ m, so propagation delay is 10⁷/(2×10⁸)=0.05 s=50 ms. Hence D. Transmission depends on message size and rate; propagation depends on distance and signal speed.
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