Multiply the linear equation p′+0.1p=e⁻⁰·¹ᵗ by integrating factor e⁰·¹ᵗ. Then $(pe^{0.1t})\prime=1$, so pe⁰·¹ᵗ=t+C. Initial data give C=20. Hence p(10)=30/e≈11.0364 μg/dL, or 11.0 to one decimal place.
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