Biomaterials and Tissue Engineering · Biomaterial Properties · 2 marks · Numerical answer
Solid spherical polymer particles of diameter 20 μm are suspended in water at 1% w/v. Polymer density is 1 g/cm³. Find the number of particles per mL, expressed as a coefficient ×10⁶, to one decimal place.
A 1% w/v suspension contains one gram per hundred millilitres, hence 0.01 g/mL. Radius is ten micrometres=10⁻³ cm. One particle has mass (4π/3)(10⁻³)³×1≈4.18879×10⁻⁹ g. Count is 0.01/m≈2.3873×10⁶ per mL. The requested coefficient rounds to 2.4.
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