GATE 2017 EE (EE2) – Question 51
For the shown network, the Thevenin voltage $V_{ab}$ is

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Correct answer: (A) −1.5 V
Explanation
Set node b to zero and let the left upper node be V1 and terminal a be Va. The right voltage source fixes its upper node at 16 V.
KCL at the left node gives $V_1/5+(V_1-V_a)/10+6=0$, or 3V1−Va=−60. At a, $(V_a-V_1)/10+V_a/10+(V_a-16)/10=0$, or 3Va−V1=16.
Solving gives **Va=−1.5 V**, so Vab=−1.5 V, **A**.
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