A batch reactor begins with 1 g/L biomass and a lag phase of 30 min. Log-phase specific growth rate is $0.00417\ \mathrm{min}^{-1}$. Find total time to reach 8 g/L, in min, rounded to 2 decimals.
After lag, exponential growth gives $X=X_0e^{\mu(t-30)}$. Thus $8=e^{0.00417(t-30)}$ and $t=30+\ln(8)/0.00417=528.67$ min. The lag time must be added to the growth time, not included in the exponential-growth duration.
More Bioreaction Engineering: Kinetics of cell growth, substrate utilization and product formation, structured and unstructured models questions
GATE 2019 BT Q25– Which cannot be the limiting substrate in the standard Monod growth model?
GATE 2019 BT Q27– What is catabolized during endogenous metabolism in batch bacterial cultivation?
GATE 2024 BT Q33– The degree of reduction (reductance) for oxalic acid (C 2H 2O 4) is .
GATE 2024 BT Q34– If the rate at which E. coli divides is 0.5 h-1, then its doubling time is h.
GATE 2024 BT Q52– Which of the following factors can affect the growth of a microbial culture in a batch…
GATE 2024 BT Q58– E. coli is inoculated in a shake flask containing nutrient rich medium. The initial number…