The shown cyclopentadienylacetate reacts with (i) one equivalent 9-BBN, (ii) H₂O₂/NaOH to give P; then (i) MsCl/Et₃N, (ii) NaOH, (iii) H₂/(Ph₃P)₃RhCl to give Q. Select P and Q.
Bulky 9-BBN hydroborates the accessible alkene face, and oxidation replaces C–B by C–OH with retention, giving the allylic alcohol P drawn in A/B. Mesylation activates that alcohol without breaking its C–O bond. Hydrolysis generates the carboxylate, whose intramolecular displacement at the mesylate-bearing carbon closes the lactone with inversion. Rh-catalyzed hydrogenation removes the remaining C=C bond. The cis-fused lactone obtained after this inversion is Q in B.
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