Correct answer: (C) The more electronegative element is leached.
Explanation
The appended key selects C, and that grading is preserved. Selective leaching removes the electrochemically more active, less noble constituent, leaving a porous residue enriched in the nobler component. Atomic weight and density do not determine that electrochemical preference, and diffusivity alone is not the criterion. The printed word “electronegative” is problematic if read as ordinary chemical electronegativity: the intended meaning is the constituent with the more negative electrode potential, not necessarily the more electronegative element on an atomic electronegativity scale.
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