A thin isotropic plate has E=210 GPa, Poisson ratio 0.3, initial x dimension 100 mm and y dimension 200 mm. Under plane stress σxx=100 MPa and σyy=240 MPa, find its extension along y in mm (one decimal place).
Plane-stress Hooke’s law gives $\epsilon_y=(\sigma_{yy}-\nu\sigma_{xx})/E=(240-0.3\times100)/210000=0.001$. Multiply by the initial y length: Δy=0.001×200=0.2 mm. The x stress reduces the y strain through Poisson coupling.
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