A complex contains one Cr, three Br and six H₂O per formula unit. Excess AgNO₃ gives 0.94 g AgBr from the source’s stated 1.0 g sample in aqueous solution. Determine its formula. Atomic weights: Cr52, Br80, Ag108, O16, H1.
The formula mass is 52+3×80+6×18=400 g/mol. A 1 g complex sample is 0.0025 mol, while 0.94/188=0.005 mol AgBr forms. Thus two bromides per complex are outside the coordination sphere, leaving one coordinated bromide and five coordinated waters. The sixth water is crystallization water: B. The source’s “1.0 g aqueous solution” must mean 1.0 g complex dissolved for this calculation; literal unspecified solution concentration would be insufficient.
More Transition Metals: Coordination chemistry – structure and isomerism, theories of bonding (VBT, CFT, and MOT). Metal-metal multiple bonds. Energy level diagrams in various crystal fields, CFSE, applications of CFT, Jahn-Teller distortion. Electronic spectra of transition metal complexes: spectroscopic term symbols, selection rules, Orgel and Tanabe-Sugano diagrams, nephelauxetic effect and Racah parameter, charge-transfer spectra. Magnetic properties of transition metal complexes. Ray-Dutt and Bailar twists, Reaction mechanisms: kinetic and thermodynamic stability, associative, dissociative substitution and redox reactions. questions
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