Mining Methods and Machinery · Mining Machinery · 2 marks · Numerical answer
A single 7-tonne-payload skip hoists from 620 m. Acceleration/deceleration are 1 m/s² and full speed 10 m/s. Loading takes 120 s and unloading 60 s; utilisation 70%. Find maximum daily capacity in tonnes, to the nearest integer.
Each acceleration and braking leg takes 10 s and 50 m. Cruise distance is 520 m, taking 52 s. One-way travel is 72 s. The single skip must return, so a cycle takes 2×72+120+60=324 s. Daily capacity is 86400×0.70×7/324=1306.67 tonnes, rounding to 1307. Counting only the loaded ascent would overestimate output.
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