GATE 2026 CE (CE1) – Question 3
At how many points will the curves $y = x^2$ and $y = -x^2 - 2x - 1$ intersect in the real $(x, y)$ plane?
Practise this question in The GATE Grind →
Show answer and explanation
Correct answer: (A) 0
Explanation
Setting the two equal gives $x^2 = -(x + 1)^2$. The left side is at least 0 and the right side is at most 0, so both would have to be 0, which needs $x = 0$ and $x = -1$ at the same time. That is impossible, so the curves never meet.