GATE 2024 CY – Question 13
The reaction of $\mathrm{XeF_2}$ with $\mathrm{HN(SO_2F)_2}$ at 273 K in $\mathrm{CF_2Cl_2}$ solvent yields
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Correct answer: (D) $\mathrm{FXeN(SO_2F)_2+HF}$
Explanation
$\text{XeF}_2$ is a fluorinating agent. $\text{HN(SO}_2\text{F)}_2$ has an acidic N–H bond (the nitrogen carries two strongly electron-withdrawing $\text{SO}_2\text{F}$ groups).
**Reaction:** the acidic hydrogen combines with a fluoride from xenon, and the amide nitrogen takes the place of the fluorine on xenon:
$$\text{XeF}_2+\text{HN(SO}_2\text{F)}_2\longrightarrow\text{FXeN(SO}_2\text{F)}_2+\text{HF}.$$
The product contains a rare xenon-nitrogen bond (option D). The other options involve oxidation or decomposition products that do not follow from this simple acid-base type substitution.