GATE 2024 CY – Question 36
Borax on treatment with NaOH and $\mathrm{H_2O_2}$ forms X. Compound X on reaction with PhCN at 60 °C in methanol–water gives Y as major product. X and Y, respectively, are
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Correct answer: (C) $\mathrm{Na_2B_2(O_2)_2(OH)_4\cdot nH_2O}$ and $\mathrm{PhCONH_2}$
Explanation
**Step 1: borax with NaOH and H₂O₂.** This is the way sodium perborate is made. The product X is the dimeric peroxoborate containing two peroxide bridges, $\text{Na}_2[\text{B}_2(\text{O}_2)_2(\text{OH})_4]\cdot n\text{H}_2\text{O}$. (Option C and D have this formula; options A and B show a monomeric formula.)
**Step 2: X with benzonitrile.** Perborate acts as a mild source of nucleophilic peroxide (as in the Radziszewski reaction). Hydroperoxide adds to the nitrile and the peroxyimidic acid transfers oxygen, giving the **amide**, **benzamide** ($\text{PhCONH}_2$). The reaction stops at the amide stage and does not hydrolyse it to benzoic acid under these mild conditions.
So X $=\text{Na}_2\text{B}_2(\text{O}_2)_2(\text{OH})_4\cdot n\text{H}_2\text{O}$ and Y $=\text{PhCONH}_2$ (option **C**).