GATE 2021 ME (ME2) – Question 36
The value of $\int_0^{\pi/2}\int_0^{\cos\theta}r\sin\theta\,dr\,d\theta$ is
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Correct answer: (B) $1/6$
Explanation
Integrate over r first to obtain $\tfrac12\int_0^{\pi/2}\cos^2\theta\sin\theta\,d\theta$. Let u=cosθ, du=−sinθdθ.
The integral is $\tfrac12\int_0^1u^2du=\mathbf{1/6}$, **B**.