GATE 2019 ME (ME1) – Question 18
During a non-flow thermodynamic process executed by a perfect gas, heat interaction equals work interaction. Which process gives this equality?
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Correct answer: (C) Isothermal
Explanation
The first law gives Q-W=ΔU. Equality Q=W therefore requires ΔU=0. For a perfect gas internal energy depends only on temperature, so temperature is unchanged: the process is **isothermal, C**. Adiabatic alone means Q=0 and need not give zero work.