GATE 2019 ME (ME2) – Question 35

Machining and Machine Tool Operations · Abrasive and non-traditional machining processes · 1 mark · Numerical answer

In electrical discharge machining, inter-electrode-gap breakdown voltage is 200 V and the RC-circuit capacitance is 50 μF. Find energy released per spark (J).

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Correct answer: 1 to 1

Explanation

In electrical discharge machining the energy released by one spark is the energy stored in the capacitor of the RC circuit, $E=\tfrac12CV^2$.

With $C=50\ \mu\text{F}=50\times10^{-6}$ F and $V=200$ V:

$E=\tfrac12(50\times10^{-6})(200)^2=\tfrac12(50\times10^{-6})(4\times10^{4})=\tfrac12(2)=1$ J.

**$E=1$ J**