$LiAlH_4$ reacts with one equivalent of $Me_3N\cdot HCl$ to give a tetrahedral compound, then another equivalent of $Me_3N\cdot HCl$ gives N. Identify N and its geometry.
Protonolysis of hydride by trimethylammonium chloride releases H2 and forms the neutral alane adduct AlH3(NMe3). Addition of a second donor amine gives five-coordinate **AlH3(NMe3)2**. Its five donor atoms adopt a trigonal-bipyramidal arrangement.
Therefore **C**, rather than a lithium-containing five-coordinate formulation.