GATE 2018 ME (ME1) – Question 64
A 2 kg block P slides down a surface and passes the lowest point Q at 20 m/s. Local radius of curvature is 2 m as shown. With g = 10 m/s², normal force at Q, to two decimals, is ______ N.
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Correct answer: 419.00 to 421.00
Explanation
At the lowest point the centripetal direction is upward. Thus $N-mg=mv^2/R$, giving $N=2(10)+2(20^2)/2=420$ N.