GATE 2018 ME (ME2) – Question 16
In the frictionless gear train shown, the leftmost 12-tooth gear receives 100 N·m torque. Find the output torque (N·m) of the rightmost 60-tooth gear.
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Correct answer: (D) 2000
Explanation
The first gear stage multiplies torque by $48/12=4$. Its shaft drives another 12-tooth gear, which drives 60 teeth, multiplying torque by 5. With no losses, $$T_{\rm out}=100\frac{48}{12}\frac{60}{12}=2000\ \mathrm{N\,m}.$$ Answer **D**.