An iron–carbon alloy at room temperature contains pro-eutectoid ferrite formed above the eutectoid temperature, and pearlite formed below it. Which description fits?
Steel below eutectoid carbon concentration first forms ferrite from austenite above the eutectoid temperature. The remaining austenite transforms into pearlite. This identifies **hypo-eutectoid steel, C**. Hyper-eutectoid steel forms pro-eutectoid cementite instead.
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