At dead centers the crank and rod are collinear, with pivot-to-slider distances 4l and 2l. Their horizontal projections are $\sqrt{(4l)^2-l^2}=l\sqrt{15}$ and $\sqrt{(2l)^2-l^2}=l\sqrt3$. Stroke is $10(\sqrt{15}-\sqrt3)=21.4093$ cm, giving **21.4 cm**.
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