A mild-steel tensile specimen of gauge length 50 mm and diameter 10 mm is extended at 4 mm/min, first from 50 to 55 mm and then 55 to 60 mm. Neglect elastic strain. Find total longitudinal true strain to two decimals.
True strains add logarithmically: $\epsilon=\ln(55/50)+\ln(60/55)=\ln(60/50)=0.18232$. Thus **0.18**. Extension speed and diameter do not affect the specified longitudinal strain.
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