Correct answer: (B) It is singular.; (D) It is not regular singular.
Explanation
Divide by the leading coefficient: $p(x)=3/[2(x-2)^2]$, $q(x)=1/[2x(x-2)]$. Coefficients are singular at 2. Regular singularity would require (x−2)p and (x−2)²q analytic there, but $(x-2)p=3/[2(x-2)]$ still has a pole. Thus the point is irregular singular: **B,D**.
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