Farm Power · Farm Power · 1 mark · Numerical answer
One kilogram of air is compressed reversibly from 100 kPa and 15 L to 2000 kPa and 1 L. Neglect other losses. Find the polytropic exponent n, to three decimals.
For a polytropic process,$pV^n$ is constant, so $p_2/p_1=(V_1/V_2)^n$. Take logarithms:$n=\ln(2000/100)/\ln(15/1)=\ln20/\ln15=1.106232$. Thus **n=1.106**. The mass cancels from this pressure–volume relation.
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