GATE 2026 AG – Question 33
A tubewell discharges $25\,\mathrm{m^3/h}$ for 10 h/day. Average irrigation depth is 80 mm and irrigation interval 20 days. At irrigation intensity 80%,find the culturable command area in hectares, to two decimals.
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Correct answer: 7.50 to 8.00
Explanation
Water available per interval is $25(10)(20)=5000$ m³. At depth $0.080$ m, it irrigates $5000/0.080=62500$ m²=6.25 ha. This is 80% of the culturable command area, so $A=6.25/0.80=\mathbf{7.81}$ ha after rounding.
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