Convert to absolute temperatures:$T_L=243.15$ K and $T_H=293.15$ K. For a reversible cycle,$Q_H/Q_L=T_H/T_L$. Thus $Q_H=70(293.15/243.15)=84.394$ kW. The difference $Q_H-Q_L\approx14.394$ kW is input power, not heat rejection. **84.40,A**.
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