Freeze100 kg shrimp from 25°C to−18°C. Freezing point is 0°C;specific heats above/below it are3.64 and 2.01 kJ/(kg·°C),and latent heat is 240 kJ/kg. Find removed heat in kJ, to one decimal.
Add sensible cooling above freezing, phase-change heat, and sensible cooling below freezing: $$Q=100[3.64(25-0)+240+2.01(0-(-18))].$$ Per kilogram these contributions are91,240,36.18 kJ, so total is **36718.0 kJ**. Applying one specific heat over the whole temperature range would omit the distinct frozen-state property.
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