Correct answer: (B) Lag time removes the initial90% of the population.
Explanation
Set $t=t_l$ in the supplied relation. Then $\log_{10}(N_0/N)=1$,so $N=N_0/10$:90% of the original population has been removed. Therefore **B** follows directly. The relation is an empirical time-offset model; its term lag should be interpreted through this printed equation rather than assuming zero killing during that interval.
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