Hourly rainfall excess is $\max(i-\phi,0)$,giving1,0,.5,0 cm. Total excess depth is 1.5 cm=.015 m. Area is 100000 m²,so direct runoff is $.015(100000)=\mathbf{1500}$ m³,**A**. The φ-index is deducted only up to the rainfall available in an interval.
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