A 2WD tractor weighs20 kN and travels at actual3 km/hour with 12% slip. Front/rear dynamic loads are40%/60%. Net traction coefficient is .42. Axle power(kW)/rear dynamic load(kN)=1.79/V, where V is theoretical km/hour speed. Find tractive efficiency in percent, to two decimals.
Rear load is 12 kN and net drawbar pull is $.42(12)=5.04$ kN. Actual speed gives drawbar power $5.04(3/3.6)=4.2$ kW. Theoretical speed is $V=3/(1-.12)=3.409091$ km/hour. Axle power is $12(1.79/3.409091)=6.3008$ kW. Efficiency is $100(4.2/6.3008)=\mathbf{66.66\%}$. The supplied empirical ratio uses V in km/hour.
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