An accelerometer at a seated tractor operator’s waist records RMS acceleration2.5 m/s². Improved seating reduces acceleration level5 dB. Find new RMS acceleration in m/s²,to three decimals.
Acceleration level uses the amplitude relation $\Delta L=20\log_{10}(a_2/a_1)$. A reduction5 dB means $a_2=2.5\cdot10^{-5/20}=1.405853$ m/s². Rounded to three decimals, the result is **1.406 m/s²**. A 10-log relation would apply to squared amplitude or energy rather than acceleration amplitude.
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