A vertical five-disc plough works.15 m deep. Disc angle40°,diameter .6 m, and overlap between successive discs at working depth .12 m. Find total cut width in m.
At depth d=.15 in a disc of radius R=.30,the horizontal chord is $c=2\sqrt{R^2-(R-d)^2}=.519615$ m. Its projected cut width is $c\sin40^\circ=.334002$ m. Five discs give $5(.334002)$ with four overlaps of .12 m: $W=1.670011-.48=\mathbf{1.19}$ m,**A**.
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