Horizontal terrace interval is 2.5/.10=25 m. The1:1 batter occupies2.5 m horizontally, leaving working width22.5 m. Original sloping ground length per interval is $25\sqrt{1+.10^2}=25.12469$ m. Area lost relative to that original surface is $(25.12469-22.5)/25.12469\times100=10.44665\%$. Thus **22.50 m and 10.45%,C**. Accounting for original ground slope explains why loss slightly exceeds the10% horizontal projection.
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