Ozone molar mass is 48 g/mol and mole fraction is $120\times10^{-9}$. Ideal-gas molar density is P/(RT),with 101325 Pa and 298 K. Thus $C=120\times10^{-9}[101325/(8.314\cdot298)]48(10^6)=235.5661$ µg/m³. Answer **235.6 µg/m³**; the factor10⁶ converts grams to micrograms.
More Atmosphere and Air Quality questions
GATE 2023 ES Q59– A 30 m³ room has ventilation500 m³/hour in/out and initially negligible VOC. A stove…
GATE 2022 ES Q48– Temperature–height profiles P, Q, R are shown. For ground-level emissions, select correct…
GATE 2021 ES Q14– An air sample has 30 ppmv CO at 25°C in the morning. The same sample is analysed at 35°C…