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GATE 2024 ES – Question 63

Environmental Management and Sustainable Development · Environmental Management Systems · 2 marks · Numerical answer

A 75 kg person drinks2.5 L/day water containing.6 mg/L lead. Find drinking-water lead exposure in mg/(kg·day),to two decimals.

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Correct answer: 0.02 to 0.02

Explanation

Daily ingested mass is $2.5(.6)=1.5$ mg/day. Normalize by body mass75 kg: $1.5/75=.020$ mg/(kg·day). Thus the requested exposure level is **.02 mg/(kg·day)**. This is intake per body mass, not a lifetime cancer-risk calculation.

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